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Camera flashes charge a capacitor to high voltage by switching the current through an inductor on and off rapidly. In what time must the 0.100 A current through a 2.00 mH inductor be switched on or off to induce a 500 V emf

Respuesta :

Answer:

The value is  [tex]\Delta t = 4.0 *10^{-7} \ s[/tex]

Explanation:

From the question we are told that

  The current is [tex]\Delta I = 0.100 \ A[/tex]

  The  inductor  is [tex]L = 2.0mH = 2.0*10^{-3} \ H[/tex]

  The voltage induced is  [tex]\epsilon = 500 V[/tex]

Generally the emf induced is mathematically represented as

      [tex]\epsilon = L * \frac{\Delta I }{\Delta t }[/tex]

Here  [tex]\Delta t[/tex] is the time taken  

=>  [tex]\Delta t = \frac{L * \Delta I }{\epsilon }[/tex]

=>  [tex]\Delta t = \frac{2*10^{-3} * 0.100 }{500 }[/tex]

=>  [tex]\Delta t = 4.0 *10^{-7} \ s[/tex]