Given:
Selling price of a ring = $50
Selling price of necklace = $30
Total pieces of jewelry sold = 25
Total sales = $1050
To find:
The number of rings and necklaces sold.
Solution:
Let number of rings sold be x and number of necklace sold be y.
Total pieces of jewelry sold = 25
[tex]x+y=25[/tex] ...(i)
Total sales = $1050
[tex]50x+30x=1050[/tex] ...(ii)
Multiply equation (i) by 30 and then subtract the result from equation (ii).
[tex]50x+30x-30(x+y)=1050-30(25)[/tex]
[tex]50x+30x-30x-30y=1050-750[/tex]
[tex]20x=300[/tex]
Divide both sides by 20.
[tex]x=15[/tex]
Substitute x=15 in (i).
[tex]15+y=25[/tex]
[tex]y=25-15[/tex]
[tex]y=10[/tex]
Therefore, the number of rings is 15 and number of necklaces is 10.
Isabella sold 10 necklaces in total
Let the amount of necklaces sold be x
Let the amount of Rings sold be y
If Isabella sold 25 pieces of jewelry, then;
x + y = 25
x = 25 -y ................1
Also, if Rings sell for $50 each, and necklaces sell for $30 each with a total sales of $1050, then;
30x + 50y = 1050 .................... 2
Substitute equation 1 into 2:
30(25-y) + 50y = 1050
750 - 30y + 50y = 1050
750 + 20y = 1050
20y = 1050 - 750
20y = 300
y = 15
Recall that x + y = 25
x =25 - y
x = 25 - 15
x = 10
Hence Isabella sold 10 necklaces in total
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