Answer: The molar mass of the gas is 31.6 g/mol
Explanation:
According to ideal gas equation:
[tex]PV=nRT[/tex]
P = pressure of gas = 3.0 atm
V = Volume of gas = 25.0 L
n = number of moles = ?
R = gas constant =[tex]0.0821Latm/Kmol[/tex]
T =temperature =[tex]27.0^0C=(27.0+273)K=300K[/tex]
[tex]n=\frac{PV}{RT}[/tex]
[tex]n=\frac{3.0atm\times 25.0L}{0.0821 L atm/K mol\times 300K}=3.04moles[/tex]
Moles =[tex]\frac{\text {given mass}}{\text {Molar mass}}[/tex]
[tex]3.04=\frac{96.0g}{\text {Molar mass}}[/tex]
[tex]{\text {Molar mass}}=31.6g/mol[/tex]
The molar mass of the gas is 31.6 g/mol
