contestada

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the
time after launch, x in seconds, by the given equation. Using this equation, find the
maximum height reached by the rocket, to the nearest tenth of a foot.
y= –16x² + 254x + 79

Respuesta :

Answer:

The maximum height is 1087.06 ft.

Step-by-step explanation:

We need to take the derivative of the equation and set it to 0.

[tex]y' = - 32x + 254 = 0\\32x = 254\\x = 7.9375[/tex]

We now can plug x = 7.9375 into the original equation.

[tex]y=-16x^{2} +254x+79\\y=-16(7.9375)^{2}+254(7.9375)+79\\y=1087.06 ft[/tex]

loganandxbox

Answer:

1087.1

Step-by-step explanation:

same as the other comment it's just that if your on delta math they make you round.