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A rocket blasts off and moves straight upward from the launch pad with constant acceleration. After 3.0 s the rocket is at a height of 80.0 m.
What are the magnitude and direction of the rocket's acceleration?
What is its speed at this time?
With explanation please!

Respuesta :

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Answer:

a) 17.8m/s² b) 53.4m/s

Explanation:

write what you know and pick an equation

s = 80m

t = 3

u = 0

s = ut + 1/2at²

80 = 0 + 1/2 x a x 3²

80 = 1/2 x a x 9

1/2 a = 80/9

a = 17.777

a = 17.8 m/s²

now we can use v = u + at

v = 0 + 17.8 x 3

v = 53.4 m/s

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