Given:
A quadrilateral WXYZ has vertices W(3, −5), X(1, −3), Y(−1, −5), and Z(1,−7).
Rule of rotation is [tex]r_{(90^\circ, O)}(WXYZ)[/tex].
To find:
The vertices after rotation.
Solution:
We know that, [tex]r_{(90^\circ, O)}(WXYZ)[/tex] means 90 degrees counterclockwise rotation around the origin.
So, the rule of rotation is defined as
[tex](x,y)\to (-y,x)[/tex]
Using this rule, we get
[tex]W(3,-5)\to W'(5,3)[/tex]
[tex]X(1,-3)\to X'(3,1)[/tex]
[tex]Y(-1,-5)\to Y'(5,-1)[/tex]
[tex]Z(1,-7)\to Z'(7,1)[/tex]
Therefore, the required vertices after rotation are W'(5,3), X'(3,1),Y'(5,-1) and Z'(7,1).
