Answer:
Option A. 52.00 amu
Explanation:
From the question given above, the following data were obtained:
Isotope A:
Mass of A = 49.946 amu
Abundance (A%) = 4.345%
Isotope B:
Mass of B = 51.941 amu
Abundance (B%) = 83.789%
Isotope C:
Mass of C = 52.941 amu
Abundance (C%) = 9.501%
Isotope D:
Mass of D = 53.939 amu
Abundance (D%) = 2.365%
Average atomic mass =.?
The average atomic mass of the unknown element can be obtained as follow:
Average atomic mass = [(Mass of A × A%)/100] + [(Mass of B × B%)/100] [(Mass of C × C%)/100] + [(Mass of D × D%)/100]
Average atomic mass = [(49.946 × 4.345)/100] + [(51.941 × 83.789)/100] + [(52.941 × 9.501)/100] + [(53.939 × 2.365)/100]
= 2.170 + 43.521 + 5.029 + 1.276
= 51.996 ≈ 52.00 amu
Therefore, the average atomic mass of the unknown element is 52.00 amu
