Respuesta :
Answer:
a. True
b. True
c. False
d. False
e. False
Step-by-step explanation:
a
[tex]x-y-z=1\\x+2y-2z=2\\3x+3y-3=3\\\\\begin{pmatrix} 1 & 1 & -1|&1\\ 2&2&-2|&2\\3&3&-3|&3\end{pmatrix}\\\\\\R_2 \rightarrow R_2-R_1\\R_3 \rightarrow R_3-R_1\\\\\begin{pmatrix} 1 & 1 & -1|&1\\ 0&0&~~0|&0\\0&0&~~0|&0\end{pmatrix}\\\\x+y-z=1[/tex]
thus there is a plane
b. If a system of solution has more than one solution than it can have infinite amount of solutions so there can be any amount of solutions except 2.
c. The solution set of a consistent rank 2 linear system with four unknowns will be a plane in the four dimensional space.
d. Following is an example which proves it wrong i-e no solution
[tex]\\\\\\\\x_1=1\\x_2+x_3=2\\x_2+x_3+x_4=0\\[/tex]
e.as shown from following example it has infinite solutions
[tex]\\\\\\\\x_1+x_2=1\\2x_1+2x_2=2\\x_3=1\\x_4=1\\[/tex]
so a system can have more than one solution