Answer:
A) 4857 kw
b) 9.1605 Kj/s
c) 4866.161 kw
d) 4866.16 kw
Explanation:
water pressure = 1 MPa
temperature = 383 k
vertical pipe height = 10 m
pipe diameter = 0.1 m
mass flow rate of pressurized water (m) = 1.5 kg/s
A) determine rate of enthalpy change
Δh = h2 - h1
= 3700 - 462 = 3238 kj/kg
enthalpy change = m( Δh ) = 1.5 * 3238 = 4857 kw
attached below is the remaining parts of the solution
From steam table
at inlet : 1 Mpa , 383 k
h1 = 462 kj/kg
Q1 = 0.0015 m^3/kg
z1 = 0 m
at outlet : 700 kPa, 873 k
h2 = 3700 kj/kg
Q2 = 0.574 m^3/kg
z2 = 10 m