the circuit consist of three resistors R1=5, R2=3, R3=4 and are connected in series to each other. A voltmeter connected in parallel to resister R2 measures voltage of 6v. what is the net in the current?

Respuesta :

Answer:

Current in the circuit= 2 A

Explanation:

Current in a Series Connection

When two or more resistors are connected in series, all of them have the same current, and the sum of their individual voltages is the total voltage applied to the circuit.

We know a voltmeter connected to R2=3Ω measures 6V. Applying Ohm's law:

[tex]V=R.I[/tex]

We can calculate the current through R2:

[tex]\displaystyle I=\frac{6}{3}=2\ A[/tex]

Since the current in R2 is the same in the rest of the resistors, the current of R1 and R3 is also 2 A.