Respuesta :
Answer:
D
Step-by-step explanation:
Recall that the area of a rectangle is given by the formula:
[tex]A=\ell w[/tex]
Where l is the the length and w is the width.
If we increase our length by 20%, this means that we add 20% or 0.2 of our old length to our old length. So, our new length will be:
[tex]\ell_{\text{new}}=\ell + 0.2\ell = 1.2\ell[/tex]
Similarly, if we increase our width by 10%, this means that we add 10% or 0.1 of our old width to our old width. So, our new width is:
[tex]w_{\text{new}}=0.1w+w = 1.1w[/tex]
Therefore, our new area will be:
[tex]A_{\text{new}}=(\ell_{\text{new}})\left(w_{\text{new}}\right)[/tex]
By substituting:
[tex]A_{\text{new}}=\left(1.2\ell\right)\left(1.1w\right)[/tex]
Multiply:
[tex]\displaystyle A_{\text{new}}=1.32\ell w[/tex]
Recall that the old area is given by:
[tex]\displaystyle A_{\text{old}} = \ell w[/tex]
So, our area increased by a factor of 1.32. In other words, our area increased by 0.32 or 32%.
Therefore, our answer is D.
Answer:
D) 32
Step-by-step explanation:
[tex]\textsf {The original equation would be :}[/tex]
[tex]\implies \mathsf {area = length \times width}[/tex]
[tex]\textsf {Now, length has been increased by 20 percent and} \\\textsf {width has been increased by 10 percent.}[/tex]
[tex]\textsf {Hence, new length and width will be :}[/tex]
[tex]\implies \textsf {new length = length + 0.2(length) = 1.2(length)}[/tex]
[tex]\implies \textsf {new width = width + 0.1(width) = 1.1(width)}[/tex]
[tex]\textsf {Now the new area will be :}[/tex]
[tex]\implies \mathsf {area' = 1.2(length) \times 1.1(width)}[/tex]
[tex]\implies \mathsf {area' = 1.32 \times length \times width}[/tex]
[tex]\textsf {Now finding the percent change in area, 'a' :}[/tex]
[tex]\implies \mathsf {a = \frac{1.32 \times length \times width - 1 \times length \times width}{1 \times length \times width}}[/tex]
[tex]\implies \textsf {a = 0.32 = 32 percent}[/tex]
The correct option is D) 32 .