Answer:
t = 1.319 s
Explanation:
Let's use the free fall relationships
y = y₀ + v₀ t + ½ g t²
In this case, as the initial velocity is dropped, it is zero and when it reaches the floor, its height is zero.
0 = y₀ + 0 + ½ g t²
t = √ (-2y₀ / g)
t = √ (- 2 8.5344 / (-9.8))
t = √ (1.7417)
t = 1.319 s
