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A net force of 200 N is applied to a 20 kg cart that is already moving at 3
m/s. The final speed of the cart was 8 m/s. For how long was the force
applied? *

Respuesta :

Answer:

t=0.5 seconds

Explanation:

Given that,

Force, F = 200 N

Mass of a cart, m = 20 kg

Initial speed of a cart, u = 3 m/s

Final speed, v = 8 m/s

Let t is the time for which the force is applied. Force applied to an object is given by :

F = ma

or

[tex]F=\dfrac{m(v-u)}{t}\\\\t=\dfrac{m(v-u)}{F}\\\\t=\dfrac{20\times (8-3)}{200}\\\\t=0.5\ s[/tex]

So, for 0.5 seconds the force is applied.

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