Answer:
runway length = 1,867.78 meters
Explanation:
This problem can be solved using equation of motion
[tex]v^2 = u^2 + \ 2as[/tex]
where
v is the final velocity
u is the initial velocity and
s is the distance a body moved to reach speed equal to final velocity .
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Given
a = 1.8 m/s2
u is the initial velocity which will be zero as the plane starts on the ground at that point speed is zero
Let S be the distance taken to reach speed 82 m/s at acceleration of 1.8 m/s^2
This , distance will be the length of runway as well.
v = 82 m/s
using the equation of motion
[tex]v^2 = u^2 + \ 2as\\=> 82^2 = 0^2 + \ 2*1.8*S\\=> 6724 = 0 + 3.6 S\\=> S = 6724/3.6 = 1,867. 78[/tex]
Thus, distance is 1,867.78 meters,
Hence , we can say that runway length should be 1,867.78 meters so that when plane lifts off its speed is 82 m/s.
