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The vertices of a right triangle are (0, 0), (1, 0), and (0, 1).




If the triangle is dilated by a factor of 3 with respect to the origin, which coordinate pair cannot be one of the vertices?


Question options:


(3, 3)



0, 0)



(0, 3)



(3, 0)

Respuesta :

MrRoyal

Answer:

(3,3)

Step-by-step explanation:

Given

[tex]Vertices: (0,0)\ (1,0)\ (0,1)[/tex]

[tex]Scale\ Factor = 3[/tex]

Required

Determine which can't be any of the new vertices

First, we need to determine the new vertices:

[tex]New\ Vertex = Scale\ Factor * Old\ Vertex[/tex]

For (0,0):

[tex]New\ Vertex = 3 * (0,0)[/tex]

[tex]New\ Vertex = (3 * 0,3 * 0)[/tex]

[tex]New\ Vertex = (0,0)[/tex]

For (1,0):

[tex]New\ Vertex = 3 * (1,0)[/tex]

[tex]New\ Vertex = (3 * 1,3 * 0)[/tex]

[tex]New\ Vertex = (3,0)[/tex]

For (0,1):

[tex]New\ Vertex = 3 * (0,1)[/tex]

[tex]New\ Vertex = (3 * 0,3 * 1)[/tex]

[tex]New\ Vertex = (0,3)[/tex]

Comparing the calculated new vertices to the list of given options; (3,3) can't be any of the new vertices of the new triangle

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