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Answer:

Moles of KOH in 1000 mL solution = 0.255 moles

Moles of KOH in 1 mL solution = 0.255/1000 = 0.000255 moles

Moles in 95 mL solution = (95 * 255)/1000000 = 24225/1000000

Moles of KOH in 95 mL 0.255M solution = 0.024225 moles

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The number of moles of KOH present in 95.0 ml of 0.255 M solution is 0.024mol

HOW TO CALCULATE NUMBER OF MOLES:

  • The number of moles of a substance can be calculated by multiplying the molarity/concentration of the substance by its volume:

no. of moles = molarity (M) × volume (L)

  • According to this question, 95.0 ml of KOH is present in 0.255 M solution, hence, the number of moles can be calculated as follows:

  • Volume of KOH = 95.0ml = 0.095L

  • no. of moles = 0.095 × 0.255

  • no. of moles = 0.024mol

  • Therefore, the number of moles of KOH present in 95.0 ml of 0.255 M solution is 0.024mol.

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