Answer:
The value is [tex]h = 52.2 \ m[/tex]
Explanation:
From the question we are told that
The velocity at which he hit the water is [tex]v = 32 \ m/s[/tex]
Generally from kinematic equation
[tex]v^2 = u^2 + 2gh[/tex]
Here the initial velocity u = 0 m/ given that the gannet started the jump from rest.
=> [tex]32^2 = 0^2 + 2*(9.8)h[/tex]
=> [tex]h = 52.2 \ m[/tex]
