Answer:
14
Step-by-step explanation:
From the given information:
suppose, Y is the number of times a coin is being flipped.
If the coin is flipped for the first time and we get H, then we have:
TTT = [tex]\dfrac{1}{2}(Y+1)[/tex]
Afterward, if we get H, then we waste two times plus the probability of this event [tex]\dfrac{1}{4}[/tex].
Therefore, we have : [tex]\dfrac{1}{4}(Y+2)[/tex]
Afterward, if we get H, then we waste three times plus the probability of this event [tex]\dfrac{1}{8}[/tex].
Therefore, we have : [tex]\dfrac{1}{8}(Y+3)[/tex]
If we got T at the third time, then;
T = [tex]\dfrac{1}{8}(3)[/tex]
Thus, average number of headsthat you’ll see until gettingTTT can be expressed as:
[tex]= \dfrac{1}{2}(Y+1)+ \dfrac{1}{4}(Y+2)+ \dfrac{1}{8}(Y+3)+ \dfrac{1}{8}(3)[/tex]
= 14
