The formula A = 1/2 S^2 expresses the area of an isosceles right
triangle in terms of the length, s, of a leg of the triangle.
Which equation expresses the length of a leg of an isosceles right
triangle in terms of the area?

Respuesta :

Answer:

[tex]s = \sqrt{2a} [/tex]

Step-by-step explanation:

A = 0.5S^2

2A = S^2

Therefore,

[tex]s = \sqrt{2a} [/tex]

To express the length in terms of the area, is an illustration of change of subject of formula.

The equation that express S in terms of the area is: [tex]S =\sqrt{2A}[/tex]

Given that:

[tex]A = \frac 12S^2[/tex]

First, multiply both sides by 2

[tex]2 \times A = \frac 12S^2 \times 2[/tex]

[tex]2 \times A = S^2[/tex]

[tex]2A = S^2[/tex]

Take positive square roots of both sides

[tex]\sqrt{2A} = \sqrt{S^2[/tex]

[tex]\sqrt{2A} = S[/tex]

Rewrite the equation as:

[tex]S =\sqrt{2A}[/tex]

Hence, the equation that express S in terms of the area is: [tex]S =\sqrt{2A}[/tex]

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