Answer:
it will take a programmer about 16.67 times to work before they are fired
Step-by-step explanation:
From the information given;
The transistion matrix for this study can be computed as:
P M X
P 0.7 0.2 0.1
M 0 0.95 0.05
X 0 0 1
where;
The probability that the programmer remains a programmer = [tex](P *P)[/tex]
The probability that the programmer turns out to be a manager = [tex](P*M)[/tex]
The probability that the programmer is being fired = [tex](P*X)[/tex]
Thus, the required number of years prior to the moment being fired for an employee y(P), for programmer and y(M) for manager is represented by ;
[tex]y(P)=1+0.7y(P)+0.2y(M)[/tex]
[tex]y(M)=1+ 0.95y(M).[/tex]
[tex]0.05y(M)=1[/tex]
y(M) = [tex]\dfrac{1}{0.05}[/tex]
y(M) =20
y(P)=1+0.7y(P)+0.2y(M)
y(P) - 0.7y(P) = 1 + 0.2y(M)
0.3y(P) = 1 + 0.2(20)=1+4
0.3y(P) = 1 + 4
0.3y(P) = 5
[tex]y(P)=\dfrac{5}{0.3}[/tex]
[tex]y(P)=16.67[/tex]
Therefore, it will take a programmer about 16.67 times to work before they are fired
