Answer:
Average net force = 0.62 N
Explanation:
We are given;
Mass; m = 1.7 kg
Initial velocity; u = 12.5 m/s
Final velocity; v = 25 m/s
time; t = 25 seconds
Now, we are told that the final velocity was 30° west of North. So, resolving this velocity along the horizontal gives;
v = 25 cos 30°
Now, using Newton's first equation of motion gives;
v = u + at
Where a is acceleration
Plugging in the relevant values gives;
25 cos 30° = 12.5 + 25a
21.6506 - 12.5 = 25a
a = (21.6506 - 12.5)/25
a = 0.3660 m/s²
Now, magnitude of the average net force would be; F = ma
F = 1.7 × 0.366
F ≈ 0.62 N