Respuesta :
Answer: 1) 65° 2) 17° 3) 53° or 37°
Step-by-step explanation:
[tex]1.\quad \cos \theta=\dfrac{adjacent}{hypotenuse}\\\\\\.\quad \quad \cos \theta=\dfrac{3}{7}\\\\\\.\qquad \qquad \theta=\cos ^{-1}\bigg(\dfrac{3}{7}\bigg)\\\\\\.\qquad \qquad \theta =65^o[/tex]
[tex]2.\quad \tan \theta =\dfrac{opposite}{adjacent}\\\\\\.\quad \quad \tan\theta =\dfrac{8}{26}\\\\\\.\qquad \qquad \theta =\tan ^{-1}\bigg(\dfrac{4}{13}\bigg)\\\\\\.\qquad \qquad \theta = 17^o[/tex]
3. Which angle do you need? I solved for both:
Bottom Right Top Left
[tex].\qquad \cos \theta=\dfrac{adjacent}{hypotenuse}\qquad \qquad \sin \theta = \dfrac{opposite}{hypotenuse}\\\\\\.\quad \quad \cos \theta=\dfrac{14}{23}\qquad \qquad \qquad \qquad \sin \theta=\dfrac{14}{23}\\\\\\.\qquad \qquad \theta=\cos ^{-1}\bigg(\dfrac{14}{23}\bigg)\qquad \qquad \quad \theta=\sin ^{-1}\bigg(\dfrac{14}{23}\bigg)\\\\\\.\qquad \qquad \theta =53^o\qquad \qquad \qquad \qquad \quad \theta =37^o[/tex]
Question 1:
cosθ = adj/hyp
cosθ = 3/7
θ = cos^-1(3/7)
θ = 65
Questions 2:
tanθ = opp/adj
tanθ = 8/26
θ = tan^-1(4/13)
θ = 17
Question 3:
Top left:
sinθ = opp/hyp
sinθ = 14/23
θ = tan^-1(14/23)
θ = 37
Bottom Right:
cosθ = adj/hyp
cosθ = 14/23
θ = cos^-1(14/23)
θ = 53
Best of Luck!