Answer:
8,000 - 24x
Step-by-step explanation:
Let
y ----> depreciated value of the car
x---> rate of depreciation
t ----> the time in months
we know that
The linear equation that represent this situation is
y=8,000-xt
For
t=2 years=2*12=24 months
substitute
y=8,,000-x(24)
y=8,000-24x