Answer:
Step-by-step explanation:
[tex] \frac{1}{3} (6x - 15) = \frac{1}{2} (10x - 4)[/tex]
Expand the terms in the bracket
That's
[tex] \frac{1 }{3} \times 6x + \frac{1}{3} ( - 15) = \frac{1}{2} (10x) + \frac{1}{2} ( - 4) \\ 2x - 5 = 5x - 2[/tex]
Subtract 5x from both sides
[tex]2x - 5x - 5 = 5x - 5x - 2 \\ - 3x - 5 = - 2[/tex]
Add 5 to both sides
[tex] - 3x - 5 + 5 = - 2 + 5 \\ - 3x = 3[/tex]
Divide both sides by - 3
[tex] \frac{ - 3x}{ - 3} = \frac{3}{ - 3} [/tex]
We have the final answer as
Hope this helps you