Respuesta :
The questions asks us to calculate the wavelength of light produced if an electron moves from n = 6 to n = 5 state in a hydrogen atom. The answer would be:
λ = [tex]7.46 * 10^{-6}[/tex] m
m = [tex]7.46 * 10^{-4}[/tex] cm
Explanation:
Please see my graphic below:
The wavelength of light produced if an electron moves from n=6 state to n=5 state of an electron in a hydrogen atom is 7.59 × [tex]10^-6[/tex] m
Using the Rydberg formula;
1/λ = 1.09737 × [tex]10^-6[/tex] (1/[tex]nf^2[/tex] - 1/[tex]ni^2[/tex])
Where;
λ = wavelength
nf = final state of the electron
ni = initial state of the electron
Substituting values;
1/λ = 1.09737 × [tex]10^7[/tex] ([tex]1/5^2[/tex] - [tex]1/6^2[/tex])
1/λ = 1.09737 × [tex]10^7[/tex] (1/25 - 1/36)
1/λ = 1.09737 × [tex]10^7[/tex] (0.04 - 0.028)
1/λ = 1.09737 × [tex]10^7[/tex] (0.012)
λ = 7.59 × [tex]10^-6[/tex] m
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