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An object increases its speed from rest to 35 m/s while traveling over a distance of
400 meters. Determine the acceleration of the object.

Respuesta :

MathPhys

Answer:

1.53 m/s²

Explanation:

Given:

Δx = 400 m

v₀ = 0 m/s

v = 35 m/s

Find: a

v² = v₀² + 2aΔx

(35 m/s)² = (0 m/s)² + 2a (400 m)

a = 1.53 m/s²

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