Answer:
A.) 3.975 m/s
B.) 0.925 m/s
Explanation:
Given that a person walks first at a constant speed of 4.90 m/s along a straight line from point A to point B and then back along the line from B to A at a constant speed of 3.05 m/s.
A) What is her average speed over the entire trip?
The average speed = (4.90 + 3.05)/2
Average speed = 7.95/2
Average speed = 3.975 m/s
B) What is her average velocity over the entire trip?
Since velocity is a vector quantity, that is, we consider both the magnitude and direction
Average velocity = ( 4.90 - 3.05)/2
Average velocity = 1.85/2
Average velocity = 0.925 m/s
