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If the mean score on a stress test is 5, the standard deviation is 2, and the distribution is normal, what would be the mean value when converted to a z distribution

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Answer: 0

Step-by-step explanation:

Given that :

Mean score on test = 5

Standard deviation on test = 2

Distribution = normal

The mean value when Converted to a z - distribution :

Zscore = (x - mean) / standard deviation.

Hence z score for the mean score will be :

X = mean score

Zscore = ( 5 - 5) / 2

Zscore = 0 / 2

Zscore = 0

Mean value when Converted to a z distribution will be 0

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