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Explain why each molecule has a higher vapor pressure at a given temperature than the other in the pair. Match the words in the left column to the appropriate blanks in the sentences on the right. a. does not exhibit dispersion forces b. does not exhibit dipole-dipole forcescc. is polar d. has a smaller molar mass e. does not exhibit hydrogen bonding . 1. The main reasons why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is that CH4____and_____. 2. The main reasons why H2CO has a higher vapor pressure at a given temperature when compared to CH3OH is that H2CO_____and_____.3. The main reason why CH3OH has a higher vapor pressure at a given temperature when compared to CH3CH2CH2OH is that CH3OH_____.

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okpalawalter8

Complete Question

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Answer:

1 The main reasons why CH4 has a higher vapor pressure at a given temperature when compared to CH3Cl is that CH4 has a smaller molar mass and does not exhibit dipole to dipole force .

2. The main reasons why H2CO has a higher vapor pressure at a given temperature when compared to CH3OH is that H2CO has a smaller molar mass and does not exhibit hydrogen bonding

3. The main reason why CH3OH has a higher vapor pressure at a given temperature when compared to CH3CH2CH2OH is that CH3OH has a smaller molar mass

Explanation:

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The higher vapor pressure of the molecules at the given temperature has been based on the molar mass and the binding between the atoms of molecules.

1. The main reasons why [tex]\rm CH_4[/tex] has a higher vapor pressure at a given temperature when compared to [tex]\rm CH_3Cl[/tex] is that  [tex]\rm CH_4[/tex]:

  • Has a smaller molar mass, and
  • Does not exhibit dipole-dipole forces

Thus options b and c are correct.

2. The main reason why [tex]\rm H_2CO[/tex] has a higher vapor pressure at a given temperature when compared to [tex]\rm CH_3OH[/tex] is that [tex]\rm H_2CO[/tex]:

  • Has a smaller molar mass, and
  • Does not exhibit hydrogen bonding

Thus options c and e are correct.

3. The main reason why [tex]\rm CH_3OH[/tex] has a higher vapor pressure at a given temperature when compared to [tex]\rm CH_3CH_2CH_2OH[/tex] is that [tex]\rm CH_3OH[/tex]:

  • Has a smaller molar mass.

Thus Option c is correct.

For more information about the Vapor pressure, refer to the link:

https://brainly.com/question/8646601

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