Answer:
Explanation:
From the question we are told that
The height is [tex]h = 0.518 \ m[/tex]
The sphere density is [tex]\rho = 22.2g/cm^3 = \frac{22.2 }{1000} * 1*10^{6} = 22200 kg/m^3[/tex]
The radius is [tex]r = 2.12 \ mm =0.00212 \ m[/tex]
Generally the power required is mathematically represented as
[tex]P = \frac{16 * \pi * \rho * r * g * h^2 * c }{3}[/tex]
substituting values
[tex]P = \frac{16 * 3.142 * 22200 * 0.00212 * 9.8 * 0.518^2 * 3.0*10^{8}}{ 3}[/tex]
[tex]P = 6.22*10^{11} \ W[/tex]
