Answer:
Option B.
Step-by-step explanation:
The given values are
E(X) = 3.2, V(X) = 1.3, E(Y) = 4.6, V(Y) = 5.1, and Cov (X, Y) = 0.
The given linear combination is
[tex]Z=4X-5Y[/tex]
Now,
[tex]E(Z)=E(4X-5Y)[/tex]
It can be written as
[tex]E(Z)=4E(X)-5E(Y)[/tex]
Now, substitute the given values.
[tex]E(Z)=4(3.2)-5(4.6)[/tex]
[tex]E(Z)=12.8-23[/tex]
[tex]E(Z)=-10.2[/tex]
Therefore, the correct option is B.