Answer:
17
Explanation:
We are given the equation:
[tex]5(3x)- 7y^2[/tex]
and asked to solve when x=3 and y=2. Therefore, we must plug 3 in for x and 2 in for y.
[tex]5(3(3))-7(2)^2[/tex]
Solve according to PEMDAS: Parentheses, Exponents, Multiplication, Addition and Subtraction.
Solve the exponent first.
⇒ (2)²= 2*2=4
[tex]5(3(3))-7(4)[/tex]
Multiply 3 and 3.
⇒3*3=9
[tex]5(9)-7(4)[/tex]
Multiply 5 and 9.
⇒5*9=45
[tex]45-7(4)[/tex]
Multiply 7 and 4.
⇒ 7*4=28
[tex]45-28[/tex]
Subtract 28 from 45.
[tex]17[/tex]
5(3x)-7y² when evaluated for x=3 and y=2 is 17