B3R4
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9. If LK MK, LK = 7x - 10, KN = x + 3, MN = 9x - 11, and KJ = 28, find LJ.

9 If LK MK LK 7x 10 KN x 3 MN 9x 11 and KJ 28 find LJ class=

Respuesta :

Answer:

[tex] LJ = 46 [/tex]

Step-by-step explanation:

Given:

[tex] LK = MK [/tex]

[tex] LK = 7x - 10 [/tex]

[tex] KN = x + 3 [/tex]

[tex] MN = 9x - 11 [/tex]

[tex] KJ = 28 [/tex]

Required:

LJ

Solution:

Step 1: create an equation to find the value of x

Since we are given that LK = MK, and LK = 7x - 10, let's find the expression for MK to get an equation.

[tex] MK + KN = MN [/tex] (segment addition postulate)

[tex] MK = MN - KN [/tex] (Subtract KN from each side)

[tex] MK = (9x - 11) - (x + 3) [/tex] (subtitution)

[tex] MK = 9x - 11 - x - 3 [/tex]

[tex] MK = 9x - x - 11 - 3 [/tex]

[tex] MK = 8x - 14 [/tex]

LK = MK, therefore,

[tex] 7x - 10 = 8x - 14 [/tex]

Subtract 8x from each side

[tex] 7x - 10 - 8x = 8x - 14 - 8x [/tex]

[tex] -x - 10 = -14 [/tex]

Add 10 to both sides of the equation

[tex] -x - 10 + 10 = -14 + 10 [/tex]

[tex] -x = -4 [/tex]

Divide both sides by -1

[tex] x = 4 [/tex]

Step 2: Find LJ

[tex] LJ = LK + KJ [/tex] (segment addition postulate)

[tex] LJ = (7x - 10) + (28) [/tex]

Plug in the value of x

[tex] LJ = 7(4) - 10 + 28 [/tex]

[tex] LJ = 28 - 10 + 28 [/tex]

[tex] LJ = 46 [/tex]