Answer:
[tex]W = 6.65 \cdot 10^{6} lbf[/tex]
Explanation:
To find the weight (W) of the pond contents first we need to use the following equation:
[tex] W = m\cdot g [/tex] (1)
Where m the mass and g is the gravity
Also, we have that the mass is:
[tex]m = \rho*V[/tex] (2)
Where ρ is the density and V the volume
We cand calculate the volume as follows:
[tex] V = L*w*d [/tex] (3)
Where L is the length, w is the wide and d is the depth
By entering equation (2) and (3) into (1) we have:
[tex]W = \rho*L*w*d*g[/tex]
[tex] W = 75.3 lbm/ft^{3}*50 m*25 m*2 m*9.81 m/s^{2} [/tex]
[tex]W = 75.3 lbm/ft^{3}*\frac{(1 ft)^{3}}{(0.3048 m)^{3}}*\frac{0.454 kg}{1 lbm}*50 m*25 m*2 m*9.81 m/s^{2} = 2.96 \cdot 10^{7} N}*\frac{0.2248 lbf}{1 N} = 6.65\cdot 10^{6} lbf[/tex]
Therefore, the weight of the pond is 6.65x10⁶ lbf.
I hope it helps you!
