Complete Question
A field mouse trying to escape a hawk runs east for 5.0m, darts southeast for 3.0m, then drops 1.0m down a hole into its burrow. What is the magnitude of the net displacement of the mouse?
Answer:
The values is [tex]s = 7.49 \ m[/tex]
Explanation:
From the question we are told that
The distance it travels eastward is [tex]x = 5.0 \ m[/tex]
The distance it travel towards the southeast is [tex]l = 3.0\ m[/tex]
The distance it travel towards the south is [tex]z = 1 \ m[/tex]
Let x-axis be east
y-axis south
z-axis into the ground
The angle made between east and south is [tex]\theta = 45^o[/tex]
The displacement toward x-axis is
[tex]x = 5 + 3cos(45)[/tex]
[tex]x = 7.12[/tex]
The displacement toward the y-axis is
[tex]y = 3 * sin (45)[/tex]
[tex]y = 2.123[/tex]
Now the overall displacement of the rat is mathematically evaluated as
[tex]s = \sqrt{7.12^2 + 2.12^2 + 1^2}[/tex]
[tex]s = 7.49 \ m[/tex]
