Answer:
b) Aluminum sphere: 11.4J
Silver sphere: 44.3 J
Explanation:
a) Mass of aluminum sphere
= 2.70(196)
= 529.20g
= 0.5292kg
Mass of silver sphere
= 10.49(196)
= 2056.04g
= 2.05604 kg
b) Work done (Joules)
= force (Newton) ×distance moved in the direction of the force (in meters)
[tex] \boxed{W = F \times d} [/tex]
To raise the sphere, the work done is against gravity.
For the formula for weight (or force of gravity), the mass needed is in kg, which we have already converted to in part (a).
Since they asked for the work done on each sphere, let's calculate the work done for the aluminium sphere first.
Aluminium sphere:
F= mg
F= 0.5292(9.8)
F= 5.18616N
W= Fd
Work done
= 5.18616(2.2)
= 11.4J (3 s.f.)
Silver sphere:
F= mg
F= 2.05604(9.8)
F= 20.149192N
W= Fd
Work done
= 20.149192(2.2)
= 44.3J (3 s.f.)
