Respuesta :

ujalakhan18

Answer:

[tex]\boxed{\sf QS = 98}[/tex]

Step-by-step explanation:

QP = PS   [Diagonals are bisected(Divided into two equal parts) by the other diagonal of parallelogram]

So,

3x - 11 = 2x + 9

3x - 2x = 9 + 11

x = 20

Now,

QS = QP + PS

QS = 3x-11+2x+9

QS = 3(20)-11+2(20)+9

QS = 60 - 11 + 40 + 9

QS = 49 + 49

QS = 98

Answer:  QS=98

Step-by-step explanation: diagonals are bisected by the other diagonal parallelogram

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