Answer:
[tex]30x\sqrt{2y}[/tex]
Step-by-step explanation:
First, multiply sqrt.(6x) by sqrt.(15xy)
That equals sqrt.[tex]\sqrt{90x^{2}y } *\sqrt{20}[/tex]
then, rewrite [tex]90x^{2} y[/tex] as (3x)^2 * (10y)
you have [tex]\sqrt{(3x)^{2} *(10y)} *\sqrt{20}[/tex]
Next, pull the terms from out under the radical, to get:
[tex]3x\sqrt{10y} *\sqrt{20}[/tex]
Now rewrite 20 as 2^2 * 5
You get [tex]3x\sqrt{10y} *(2\sqrt{5} )[/tex]
Multiply everything together to get: [tex]6x\sqrt{50y}[/tex]
Now rewrite 50 y as 5^2 * 2y
You end up with [tex]6x\sqrt{5^{2}*(2y)}[/tex]
Then, pull out the terms from under the radical. You get:
[tex]6x(5\sqrt{2y})[/tex]
Finally, multiply the 5 and 6 together to get: [tex]30x\sqrt{2y}[/tex]
