Respuesta :

VidK

Answer:

1: x = -1

2: x = 3

3: x = -3

Step-by-step explanation:

f(x)=x^3+x^2−9x−9

f(x)=x^2(x+1) −9x−9

f(x) = x^2(x+1) - 9(x+1)

f(x)= (x+1)(x^2-9)

f(x) =(x+1)(x-3)(x+3)

Answer:

[tex]\boxed{x=-1, \ x=-3, \ x=3}[/tex]

Step-by-step explanation:

The zeros of a function are the values of x when f(x) = 0.

[tex]x^3 +x^2-9x-9=0[/tex]

Factor left side of the equation.

[tex]x^2(x +1)-9(x+1)=0[/tex]

Take (x+1) common.

[tex](x^2-9)(x+1)=0[/tex]

Set factors equal to 0.

First possibility:

[tex]x^2 -9=0[/tex]

[tex]x^2 =9[/tex]

[tex]x=\± \sqrt{9}[/tex]

[tex]x=\± 3[/tex]

[tex]x=-3 \ \mathrm{or} \ x=3[/tex]

Second possibility:

[tex]x+1=0[/tex]

[tex]x=-1[/tex]

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