A cylinder containing 14.71 L of helium gas at a pressure of 169.1 atm is to be used to fill toy balloons to a pressure of 1.086 atm. Each inflated balloon has a volume of 2.414 L. What is the maximum number of balloons that can be inflated? Report your answer to 1 decimal place. (Remember that 14.71 L of helium at 1.086 atm will remain in the exhausted (empty) cylinder)

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Answer:

The number of balloons is 948.8.

Explanation:

The number of balloons can be calculated as follows:

[tex] N = \frac{V_{f}}{V_{T}} [/tex]

Where:

[tex]V_{f}[/tex]: is the volume at 1.086 atm

[tex]V_{T}[/tex]: is the balloon volume = 2.414 L  

The volume at 1.086 atm can be found using Boyle's law:

[tex] P_{i}V_{i} = P_{f}V_{f} [/tex]

[tex] V_{f} = \frac{P_{i}V_{i}}{P_{f}} = \frac{169.1 atm*14.71 L}{1.086 atm} = 2290.5 L [/tex]

Now, the number of balloons is:

[tex] N = \frac{V_{f}}{V_{T}} = \frac{2290.5 L}{2.414 L} = 948.8 [/tex]

Therefore, the number of balloons is 948.8.

I hope it helps you!