Answer:
first option
Step-by-step explanation:
Given
[tex]\frac{15}{x}[/tex] + 6 = [tex]\frac{9}{x^2}[/tex]
Multiply through by x² to clear the fractions
15x + 6x² = 9 ( subtract 9 from both sides )
6x² + 15x - 9 = 0 ( divide through by 3 )
2x² + 5x - 3 = 0 ← in standard form
Consider the factors of the product of the coefficient of x² and the constant term which sum to give the coefficient of the x- term.
product = 2 × - 3 = - 6 and sum = + 5
The factors are + 6 and - 1
Use these factors to slit the x- term
2x² + 6x - x - 3 = 0 ( factor the first/second and third/fourth terms )
2x(x + 3) - 1(x + 3) = 0 ← factor out (x + 3) from each term
(x + 3)(2x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
2x - 1 = 0 ⇒ 2x = 1 ⇒ x = 0.5
Solution set is { - 3, 0.5 }
