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The people who responded to a survey reported that they had either brown, green, blue, or hazel eyes. The results of the survey are shown in the table. A 2-column table has 4 rows. The first column is labeled Eye Color with entries brown, green, blue, hazel. The second column is labeled Number of People with entries 20, 6, 17, 7. What is the probability that a person chosen at random from this group has brown or green eyes? StartFraction 3 Over 25 EndFraction StartFraction 7 Over 25 EndFraction StartFraction 13 Over 25 EndFraction StartFraction 17 Over 25 EndFraction

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MathPhys

Answer:

13/25

Step-by-step explanation:

The total number of people is 20 + 6 + 17 + 7 = 50.

Of these, the number that have brown or green eyes is 20 + 6 = 26.

So the probability is 26/50, which reduces to 13/25.

The probability that a person chosen at random from this group has brown or green eyes is; 13/25

How to find the probability?

From the given data values, we can deduce that;

Total number of people = 20 + 6 + 17 + 7 = 50.

Now, the total number of people that have brown or green eyes is;

Total(brown or green eyes) = 20 + 6 = 26.

Thus, the probability that a person chosen at random from this group has brown or green eyes is;

P(brown or green eyes) = 26/50 =  13/25.

Read more about Probability at; https://brainly.com/question/251701

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