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Four identical point charges (+6.0 nC) are placed at the corners of a rectangle which measures 6.0 m×8.0 m. If the electric potential is taken to be zero at infinity, what is the potential at the geometric center of this rectangle

Respuesta :

Substitute the values
onyebuchinnaji

The electric potential at the geometric center of this rectangle is determined as 43.2 V.

Potential at the center of the rectangle

Potential at the center of the rectangle is calculated as follows;

  • Let the distance from each corner to the center = x
  • Let the length = a
  • Let the breadth = b

Distance from each corner to the center is calculated as follows;

[tex]x = \sqrt{(a/2)^2 + (b/2)^2}[/tex]

Potential due to four point charges is calculated

[tex]V = \frac{kq}{x} \\\\V =4 (\frac{kq}{x} )\\\\V = 4(\frac{kq}{\sqrt{(a/2)^2 + (b/2)^2} } )\\\\V = \frac{4 \times 9\times 10^{9}\times 6\times 10^{-9}}{\sqrt{(6/2)^2 + (8/2)^2} } \\\\V = \frac{4 \times 9\times 10^{9}\times 6\times 10^{-9}}{5} \\\\V = 43.2 \ Volts[/tex]

Learn more about electric potential here: https://brainly.com/question/14306881

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