Answer:
B
Step-by-step explanation:
Given a quadratic equation in standard form, ax² + bx + c = 0 ( a ≠ 0 )
Then the sum of the roots = - [tex]\frac{b}{a}[/tex]
A 2x² - 3x + 6 = 0
with a = 2 and b = - 3
sum of roots = - [tex]\frac{-3}{2}[/tex] = [tex]\frac{3}{2}[/tex] ≠ 3
B - x² + 3x - 3 = 0
with a = - 1 and b = 3
sum of roots = - [tex]\frac{3}{-1}[/tex] = 3 ← True
C [tex]\sqrt{2}[/tex] x² - [tex]\frac{3}{\sqrt{2} }[/tex] x + 1
with a = [tex]\sqrt{2}[/tex] and b = - [tex]\frac{3}{\sqrt{2} }[/tex]
sum of roots = - [tex]\frac{-\frac{3}{\sqrt{2} } }{\sqrt{2} }[/tex] = [tex]\frac{3}{2}[/tex] ≠ 3
D 3x² - 3x + 3 = 0
with a = 3 and b = - 3
sum of roots = - [tex]\frac{3}{-3}[/tex] = 1 ≠ 3
Thus the equation with sum of roots as 3 is B
