Hey there! I'm happy to help!
If we add Machine 1's 459 satisfactory pistons and 51 unsatisfactory pistons, we get 510 total pistons.
If we add Machine 2's 360 satisfactory pistons and 40 unsatisfactory pistons, we get 400 total pistons.
First, we want to find the probability of choosing an unsatisfactory piston from Machine 1.
We see that 51/510 (unsatisfactory pistons out of total pistons) simplifies to equal 1/10, so there is a 1/10 chance of getting an unsatisfactory piston from Machine 1.
For Machine 2, there are 360 satisfactory and 400 total. This gives us 360/400, which simplifies to 9/10.
Now, we multiply our two probabilities together to find the probability that they both happen.
1/10×9/10=9/100
Therefore, the probability that a piston chosen from Machine 1 is unsatisfactory and the piston chosen from Machine 2 is satisfactory is 9/100 or 9%.
Have a wonderful day! :D
