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Hank’s teacher asked him to verify that the product (y−3)(y2+3y+9) is a difference of cubes. He used the distributive property to multiply the binomial times the trinomial. Before simplifying, his product was a polynomial of the form y3+3y2+ay−3y2−ay−27. What is the value of a in the polynomial? 3 9 18 27

Respuesta :

mathmate

Answer:

a = 9

Step-by-step explanation:

In the product (y−3)(y2+3y+9), we can get the first degree term of y in two ways,

y*(9),  or -3*(3y)...............value in parentheses are from the second factor

therefore a = 9

mberisso

Answer:

a = 9

Step-by-step explanation:

Let's work on the product to answer the question:

[tex](y-3)\,(y^2+3y+9)= y^3+3y^2+9y-3y^2-9y-27[/tex]

therefore the value of the requested "a" is 9

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