Hi There! Can someone please help me with this Maths Question as soon as possible. I will mark the brainliest. Write each calculation as a single power. a) 8^5 multiplied by 8^4 b) 3^11 multiplied by 3 c)9^3 multiplied by 9^7 multiplied by 9^6 d) 7^7 ÷ 7 e) 12^10 ÷ 12^5 f) (6^3)^6

Respuesta :

Padoru

I'll be using the following properties about exponents:

[tex]a^b \times a^c=a^{b+c}[/tex]

[tex]a^b \div a^c=a^{b-c}[/tex]

[tex](a^b)^c=a^{bc}[/tex]

where a, b, and c are some positive integers

Part a:

[tex]8^5 \times 8^4 = 8^{5+4}=8^9[/tex]

Part b:

[tex]3^{11} \times 3 = 3^{11} \times 3^{1} = 3^{11+1} = 3^{12}[/tex]

Part c:

[tex]9^3 \times 9^7 = 9^{3+7}=9^{10}[/tex]

Part d:

[tex]7^7 \div 7 = 7^7 \div 7^1 = 7^{7-1}=7^6[/tex]

Part e:

[tex]12^{10} \div 12^5 = 12^{10-5}=12^5[/tex]

Part f:

[tex](6^3)^6 = 6^{6 \times 3} = 6^{18}[/tex]

These should be all the answers. Let me know if you need any clarifications, thanks!