Answer:
[tex]\large \boxed{\sf 15 \ \ and \ \ 24 \ \ }[/tex]
Step-by-step explanation:
Hello,
We can write the following, x being the second number.
[tex](2x-6)^2+x^2=801\\\\6^2-2\cdot 6 \cdot 2x + (2x)^2+x^2=801\\\\36-24x+4x^2+x^2=801\\\\5x^2-24x+36-801=0\\\\5x^2-24x-765=0\\\\[/tex]
Let's use the discriminant.
[tex]\Delta=b^4-4ac=24^2+4*5*765=15876=126^2[/tex]
There are two solutions and the positive one is
[tex]\dfrac{-b+\sqrt{b^2-4ac}}{2a}=\dfrac{24+126}{10}=\dfrac{150}{10}=15[/tex]
So the solutions are 15 and 15*2-6 = 30-6 = 24
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
