Respuesta :
Answer: The answer is 0.1350
Step-by-step explanation:
Given data
n=36
p=1/2
q=1/2
X=18
O=3
U = 18
a. With n = 36 and p = q = 1/2, you may use the normal approximation with µ = 18 and o = 3. X = 18 has real limits of 17.5 and 18.5 corresponding to z = -0.17 and z = +0.17. p = 0.1350.
The probability that a subject would guess exactly 18 correct in a series of 36 trials is 0.1350.
Given that,
ESP experiment subjects must predict whether a number randomly generated by a computer will be odd or even.
We have to determine,
What is the probability that a subject would guess exactly 18 correct in a series of 36 trials?
According to the question,
Number of trials n = 36
The probability must per whether a number randomly generated by a computer will be odd is 1/2 or even is 1/2.
By using the normal approximation,
[tex]\mu = 18 \ and \ \sigma = 3[/tex]
Therefore,
X = 18 has real limits of 17.5 and 18.5 corresponding to z = -0.17 and z = +0.17.
p = 0.1350
Hence, the probability that a subject would guess exactly 18 correct in a series of 36 trials is 0.1350.
To know more about Probability click the link given below.
https://brainly.com/question/17090368
