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Suppose that a server sends four packets of audio data, in 15 seconds each. The first is sent by the server exactly at noon (12:00:00), while each of the three successive packets is sent immediately after the completion of its predecessor. The client, on the other hand, receives the four packets beginning at 12:00:03, 12:00:20, 12:00:41, 12:00:59 respectively. What is the smallest delayed wait time (buffer) in seconds that would ensure the client had seamless playback (i.e. each packet plays immediately after the previous one ends)?

Respuesta :

akindelemf

Answer:

15

Explanation:

for seamless playback each packet should be played before their predecessor so

4th packet will start at 12:01:03

3rd packet will start at 12:00:48

2nd packet will start at 12:00:33

1st packet will start at 12:00:18

as first packet arrives at 12:00:03 so wait time is 15 seconds for seamless playback

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